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(B) The reaction is an acid-catalyzed dehydration of an alcohol. $1$. Protonation of the hydroxyl group occurs to form a good leaving group $(-OH_2^+)

Vedclass · Accepted Answer

Ethylidene cyclohexane

Vedclass · Answer

(B) The reaction is an acid-catalyzed dehydration of an alcohol. $1$. Protonation of the hydroxyl group occurs to form a good leaving group $(-OH_2^+)$. $2$. Loss of water generates a primary carbocation: $	ext{cyclohexyl-CH}_2^+$. $3$. $A$ $1,2$-hydride shift occurs to form a more stable secondary carbocation: $	ext{cyclohexyl-CH}^+-	ext{CH}_3$. $4$. $A$ subsequent $1,2$-hydride shift from the ring carbon occurs to form a more stable tertiary carbocation: $	ext{cyclohexyl}^+-	ext{CH}_2-	ext{CH}_3$ (where the positive charge is on the ring carbon). $5$. Elimination of a proton from the adjacent carbon leads to the most substituted alkene,which is ethylidene cyclohexane,as it has $7 \alpha$-hydrogens,making it the most stable (major) product.

Major product $(A)$ is:

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